how to count number of palindromes in the sentenceClosed

Question

hello everyone;

can anybody teach me how to make a program using c language that would count the number of palindromes in a sentences  and display the palindromes disregarding special characters...

example:    Enter your sentence:   " Ana and hannah together with her dad went to the beach.

number of palindromes: 3   ana hannah dad

i really need help;

ac3mark · Answer

Well, lets break it down.


0. load all variables-IE (PALCOUNT=0; sentance=""; dim wordarray()
1.Trap whole sentence in a variable
2.Count the number of spaces in the sentence
(IE 10-one_two_three_four_five_six_seven_eight_nine_ten_eleven)
 3. Make an array with 10+1 slots-populate each element in array as word - redim your array with the count [wordarray(11)].
4.  Loop through array and get the word, making another variable for the current word being scoured.
5. Make a logical check with the most right character (last character), with the first.
6. If it passes that test, then check the rest of the characters to see if match working from outter chars into inner.
7. If it passes increment variable of PALCOUNT++;

I am certain that you have this wireframe built but are looking for the actual code.  I like to guide and advise, attempting to encourage to do your own research for particulars.  I am certain Buno can come up with the C code for this logic.

BunoCS · Answer

I'm here ;)

I have a solution...BUT, I will not do all the stuff! I'm waiting for your contribution =)

To check if a word is a palindrome, you just have to follow the points 5, 6 of the above ac3mark's algorithm. I propose you a code a little more optimized to do this check. I hope you're a friend of pointers ;)
int isPalindrome(char *word) {   // init pointers  char *c, *d;    // set the 1st pointer to the 1st character  c = d = word;     // set the 2nd pointer to the last character  while(*d)    d++;   d--;    // process the word and check the characters:  // the 1st with the last  // the 2nd with the 2nd to last  // etc.  // until the first difference or the middle  while(c < d) {     if(*c != *d)        return 0; // if characters are differents, it is not a palindrome    c++; d--;   }     // yeah! it is a palindrome  return 1; }

Now, all you have to do is to cut your sentence into words. Based on the code I've given to you for counting sentences inside a paragraph, it will be easy...

Feel free to ask for advices if you need help. And I said help and not entire code ;)
@+ 
Buno, Modo CS-CCM 
The urgent is done, the impossible is underway. For miracles, envisage a time ...

gealon2024 · Answer

hi void display(good day);

i have here a simple snippets


int main(){


char a[100],b[100];
int i,k;



clrscr();

printf("Type the string: ");
gets(a);

k=strlen(a)-1;

for(i=0; i<strlen(a); i++){
b[i]=a[k];
k--;
}

b[strlen(a)]='\0';

k=strcmp(a,b);

if (k==0){
printf("palindrome");
}
else{

printf("not palindrome");

}

getch();

}


it will print "palindrome" if the input string is palindrome but will print "not palindrome" if I input a two word palindrome string. Example: "eju huje".

the main problem is if I input a string:

it will count and display a 3 or more palindrome words:

Example:    "my dad and mom went to Glenelg, Scotland"

output:

          number of palindrome words: 3   dad mom Glenelg
              

thank you ;




BunoCS · Answer

Yes, it's because you must take care of space character.
Just have to "delete" them before the comparison

gealon2024 · Answer

yes!

the first thing I need to do is remove all the spaces and punctuation, so
"eju, huje"

gets stored as

"ejuhuje"

So that when I reverse, it will work as expected. 

i work a hard time in it and still I can't get

BunoCS · Answer

Hi,
Here is a code, with pointers, which should take care of space characters  
int isPalindrome(char *text){   // init pointers  char *c, *d;    // set the 1st pointer to the 1st character  c = d = text;     // set the 2nd pointer to the last character  while(*d)    d++;   d--;    // process the text and check the characters:  // the 1st with the last  // the 2nd with the 2nd to last  // etc.  // until the first difference or the middle  // doesn't take care of space characters  while(c < d) {     while(*d == 32) // 32 is the space character ASCII value        d--; // jump over space character    if(c >= d)        break; // OK     while(*c == 32)        c++; // jump over space character    if(c >= d)        break; // OK     if(*c != *d)        return 0; // if characters are differents, it is not a palindrome            c++;     d--;   }     // yeah! it is a palindrome  return 1; } 

If you want to use the "string methods" (strlen, strcmp,...), you can see the strrev() method (http://www.warpspeed.com.au/cgi-bin/inf2html.cmd?..%5Chtml%5Cbook%5CToolkt40%5CXPG4REF.INF+275 used to reverse a string. And..oh! There is an example of palidrome detection on the above link ;)

Good luck and feel free to ask for advices

How to count number of palindromes in the sentence

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