Using .bat file to open file in diff location

Issue

I'm working on developing a menu for a USB flash drive.

I have .bat file that opens a spreadsheet with a program that is installed on the flash drive.
The code looks something like this:

Start /d \Folder1\folder2\folderofprogram Name of program.exe "Name of file.ods"

This code works well but the problem is I need to have the file in the same directory as the program.
Is there a way to make the .bat file open the file from a different directory on the USB flash drive?

I think this is a simple problem but was not able to find any information about it.

Solution

Use UNC path name. so something like this:

 \\computername\folder\filename 

or

\\mypc\c:\windows\testfile.exe 

Note

Thanks to Neomagus for this tip on the forum.