IF fnct

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rm - 2 Jul 2009 à 08:39
venkat1926 Posts 1863 Registration date Sunday 14 June 2009 Status Contributor Last seen 7 August 2021 - 3 Jul 2009 à 05:08
Hello,
How do I nest an IF function that is more than 8-deep, can i be given some techniques.

rubara

3 responses

venkat1926 Posts 1863 Registration date Sunday 14 June 2009 Status Contributor Last seen 7 August 2021 811
2 Jul 2009 à 19:50
mubashir aziz Posts 190 Registration date Sunday 12 April 2009 Status Member Last seen 16 February 2010 166
2 Jul 2009 à 22:59
yes sure you can see below solution from mine ..... you can use upto 36 IF's and 37 conditions ....

you can paste this code in B3 and in A3 write alphabet from A-Z and numeric from 0-9 and try to write some special char and see the result in B3 ..... There are many ways to get the same result but i especially made this formula to know how of nested IF's ........



B3=IF(OR(A3="a",A3="b",A3="c",A3="d",A3="e",A3="f",A3="g",A3="h"),IF(A3="a",1,IF(A3="b",2,IF(A3="c",3,IF(A3="d",4,IF(A3="e",5,IF(A3="f",6,IF(A3="g",7,8))))))),IF(OR(A3="i",A3="j",A3="k",A3="l",A3="m",A3="n",A3="o"),IF(A3="i",9,IF(A3="j",10,IF(A3="k",11,IF(A3="l",12,IF(A3="m",13,IF(A3="n",14,15)))))),IF(OR(A3="p",A3="q",A3="r",A3="s",A3="t",A3="u"),IF(A3="p",16,IF(A3="q",17,IF(A3="r",18,IF(A3="s",19,IF(A3="t",20,21))))),IF(OR(A3="v",A3="w",A3="x",A3="y",A3="z"),IF(A3="v",22,IF(A3="w",23,IF(A3="x",24,IF(A3="y",25,26)))),IF(OR(A3=1,A3=2,A3=3,A3=4),IF(A3=1,"N1",IF(A3=2,"N2",IF(A3=3,"N3","N4"))),IF(OR(A3=5,A3=6,A3=7),IF(A3=5,"N5",IF(A3=6,"N6","N7")),IF(OR(A3=8,A3=9),IF(A3=8,"N8","N9"),IF(A3=0,"Zero","Non of Single Alphabet / Single Numerics"))))))))





venkat1926 Posts 1863 Registration date Sunday 14 June 2009 Status Contributor Last seen 7 August 2021 811
3 Jul 2009 à 05:08
thank you very much