Code for the below scenario - excel vba

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jhakas Posts 1 Registration date Tuesday August 27, 2013 Status Member Last seen August 27, 2013 - Aug 27, 2013 at 05:59 AM
 jhakas - Sep 6, 2013 at 05:16 AM
Good Morning/Evening ,
I need help in coding the below scenario.
I have to code in excel vba and have requirement to look for 2 rows .
1st row has the email id with name of the person .
2nd row has the number of working hours .

For each email id/person we have 5 working hours columns with "8.5" as value . I have to check if all values are equal to "8.5" otherwise sent the email to that person .

This has to be done for all the email id /person in the 1st row till the end .

In excel it would be like :

1 XYC@gmail.com XYC ABC@gmail.com ABC ............
2
3
4
5
6 8.5 8.5 8.5 8.5 8.5 8.5 8.5 8.5 8.5 8.5 .......
Related:

5 responses

Blocked Profile
Aug 27, 2013 at 10:50 AM
Ok so i have wireframed some code for the logic, but I am relectant to post automated code for sending emails.

This is very static, and I am certain there will be others to follow:
Sub SendEMail()
Dim r As Integer
Dim cnt As Integer
Dim temphour As String
Dim emailstring As String
Dim OutApp As Object
Dim OutMail As Object
Dim lastrow As Integer
lastrow = 10
For cnt = 1 To lastrow
For r = 2 To 5 'colums fo rhourly data, make certain they match what you are looking at
'find the hours in the columns after email, if not 8.5 then get the email in colum 1 of the current line
temphour = Sheet1.cells(cnt, r)
If temphour <> "8.5" Then
emailstring = Sheet1.cells(cnt, 1) 'gets the email
'**************************************
Set OutApp = CreateObject("Outlook.Application")
Set OutMail = OutApp.CreateItem(0)

On Error Resume Next
With OutMail
.To = emailstring
.CC = ""
.BCC = ""
.Subject = "Daily hours"
.Body = "Hours not 8.5 for " & WeekdayName(r - 1, 0, vbSunday)
.Display
End With
On Error GoTo 0

Set OutMail = Nothing
Set OutApp = Nothing
'*******************************************
End If
Next r
Next cnt

End Sub
0
Blocked Profile
Aug 27, 2013 at 10:53 AM
Here is a simple wire frame...


I hope this isn't for a school project.

Sub SendEMail()
Dim r As Integer
Dim cnt As Integer
Dim temphour As String
Dim emailstring As String
Dim OutApp As Object
Dim OutMail As Object
Dim lastrow As Integer
lastrow = 10
For cnt = 1 To lastrow
For r = 2 To 5 'colums fo rhourly data, make certain they match what you are looking at
'find the hours in the columns after email, if not 8.5 then get the email in colum 1 of the current line
temphour = Sheet1.cells(cnt, r)
If temphour <> "8.5" Then
emailstring = Sheet1.cells(cnt, 1) 'gets the email
'**************************************
Set OutApp = CreateObject("Outlook.Application")
Set OutMail = OutApp.CreateItem(0)

On Error Resume Next
With OutMail
.To = emailstring
.CC = ""
.BCC = ""
.Subject = "Daily hours"
.Body = "Hours not 8.5 for " & WeekdayName(r - 1, 0, vbSunday)
.Display
End With
On Error GoTo 0

Set OutMail = Nothing
Set OutApp = Nothing
'*******************************************
End If
Next r
Next cnt

End Sub

Have fun. If it doesn't work in your sheet, then make certain al of the cell references are coorect, as I am trying to wireframe it, and not give you an absolute asnwer.
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TrowaD Posts 2921 Registration date Sunday September 12, 2010 Status Moderator Last seen December 27, 2022 555
Aug 27, 2013 at 11:18 AM
Hi JHakas,

Not sure what you want for an answer so let's give this a try.
When you run the code below, row 7 will be used to place some text to let you know to sent an e-mail.
Here is the code:
Sub RunMe()
Dim lCol, x As Integer
lCol = Cells(6, Columns.Count).End(xlToLeft).Column
x = 1
Do
    If Cells(6, x).Value <> 8.5 Or _
    Cells(6, x + 1).Value <> 8.5 Or _
    Cells(6, x + 2).Value <> 8.5 Or _
    Cells(6, x + 3).Value <> 8.5 Or _
    Cells(6, x + 4).Value <> 8.5 Then
        Cells(7, x).Value = "E-mail needs to be sent"
    End If
    x = x + 5
Loop Until x + 4 > lCol

End Sub

Best regards,
Trowa
0
Blocked Profile
Aug 28, 2013 at 10:37 AM
I have a nested loop solution that formats emails. But I was not certain of the structure, so this is given:

A1-email@email.com B1-anotheremail@email.com etc....
A2-8.5 B2-8
A3-8.5 B2-8.5
A4-8.5 B2-8.5
A5-8.5 B2-8.5
A6-8.5 B2-8


The following code will generate an email for the Monday, and Friday for the User Anotheremail@email.com

Sub SendEMail()
Dim r As Integer
Dim cnt As Integer
Dim temphour As String
Dim emailstring As String
Dim OutApp As Object
Dim OutMail As Object
Dim lastrow As Integer
lastrow = Sheet1.Cells(1, Columns.Count).End(xlToLeft).Column
For cnt = 1 To lastrow
For r = 2 To 5 'colums fo rhourly data, make certain they match what you are looking at
'find the hours in the columns after email, if not 8.5 then get the email in colum 1 of the current line
temphour = Sheet1.Cells(r, cnt)
If temphour <> "8.5" Then
emailstring = Sheet1.Cells(1, cnt) 'gets the email
'MsgBox (emailstring)
'**************************************
Set OutApp = CreateObject("Outlook.Application")
Set OutMail = OutApp.CreateItem(0)

On Error Resume Next
With OutMail
.To = emailstring
.CC = ""
.BCC = ""
.Subject = "Daily hours"
.Body = "Hours not 8.5 for " & WeekdayName(r, 0, vbSunday)
.Display
End With
On Error GoTo 0

Set OutMail = Nothing
Set OutApp = Nothing
'*******************************************
End If
Next r
Next cnt

End Sub
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Thanks ac3mark for the Code !!!! A Real help for me ..

I have a different format in which both times parse through colunms .

A1-email@email G6-anotheremail@email
A6-8.5,B6-8.5,C6-8.5,D6-8.5,E6-8 G6-8.5,H6-8.5,I-8.5,J-8.5,K-8.5

In the above case email should go anotheremail@email , I did some changes to the above to suit the condition but getting problem. Mail was sent for both A1 and G6 .
Seems to be initialization problem with variable "temphour" .

lastrow = Sheet1.Cells(1, Columns.Count).End(xlToLeft).Column
For cnt = 1 To lastrow
For r = 1 To 5
temphour = Sheet1.Cells(6, r)
If temphour <> "8.5" Then
emailstring = Sheet1.Cells(1, cnt)
If emailstring Like "*@*" Then
'**************************************
Set OutApp = CreateObject("Outlook.Application")
Set OutMail = OutApp.CreateItem(0)

On Error Resume Next
With OutMail
.To = emailstring
.CC = ""
.BCC = ""
.Subject = "Daily hours"
'.Body = "Hours not 8.5 for " & WeekdayName(r, 0, vbSunday)
.Body = "Hours not 8.5 for this week"
.Save
End With
On Error GoTo 0

Set OutMail = Nothing
Set OutApp = Nothing
'*******************************************
End If

End If
Next r
Next cnt

End Sub
0
Blocked Profile
Sep 5, 2013 at 08:30 AM
I am gald it helped you. So you have corrected to make it work for you, or do you still need help with the variable that you have coded as static?
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I need help , as when i am going for all the colums values <> 8.5 starting from A6 .
i used temphour = Sheet1.Cells(6, r) as i need to look for every 5 occurence in Row 6 .
But by doing this the code is not working properly .
Need an alternative by which i can parse through columns in Row 6 .
0

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Blocked Profile
Aug 28, 2013 at 10:41 AM
Good Morning,

I have came up with this...and thank you to Ambucias for restoring the messages.


Sub SendEMail()
Dim r As Integer
Dim cnt As Integer
Dim temphour As String
Dim emailstring As String
Dim OutApp As Object
Dim OutMail As Object
Dim lastrow As Integer
lastrow = Sheet1.Cells(1, Columns.Count).End(xlToLeft).Column
For cnt = 1 To lastrow
For r = 2 To 5 'colums fo rhourly data, make certain they match what you are looking at
'find the hours in the columns after email, if not 8.5 then get the email in colum 1 of the current line
temphour = Sheet1.Cells(r, cnt)
If temphour <> "8.5" Then
emailstring = Sheet1.Cells(1, cnt) 'gets the email
'MsgBox (emailstring)
'**************************************
Set OutApp = CreateObject("Outlook.Application")
Set OutMail = OutApp.CreateItem(0)

On Error Resume Next
With OutMail
.To = emailstring
.Subject = "Daily hours"
.Body = "Hours not 8.5 for " & WeekdayName(r, 0, vbSunday)
.Display
End With
On Error GoTo 0

Set OutMail = Nothing
Set OutApp = Nothing
'*******************************************
End If
Next r
Next cnt

End Sub
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Blocked Profile
Aug 28, 2013 at 10:45 AM
The above code is for the following structure:

1A-email@email.com 1B-anotheremail@email.com
2a-8.5 2b-8
3a-8.5 3b-8.5
4a-8 4b-8.5
5a-8.5 5b-8.5
6a-8.5 6b-8

Based on the example, the code will start an email for User email@email.com for 8 hour on Wednesday (4A), and User anotheremail@email.com for 8 hours on Monday (2B), and 8 hours on Friday (6B).

I hope this helps.
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