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Parse error: syntax error, unexpected $end in C:\AppServ\www\Curso Web\06Aplicac

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 - - Latest reply: Pepej89
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 - Aug 21, 2019 at 10:54 AM
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Ya intente de todo este es mi código sin modificar

else
{
//echo "NOOOOO";
$respuesta = "<div class='error'>Error: No se ejecuto la consulta a la Base de Datos</div>";
}

$mysql->close();

return printf($respuesta);
}
?>

Y este modificado

else
{
//echo "NOOOOO";
$respuesta = "<div class='error'>Error: No se ejecuto la consulta a la Base de Datos</div>";
}

$mysql->close();

return printf($respuesta);
}
<?php ?>
<?!

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Thank you
This is English only, put looking at your code, the result of BOTH ELSE, are the same. MODIFY your code to have two different results based on the logic!
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Pepej89
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Buenos días es que el error lo marca en la última línea si viera que al final no es la misma línea
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