Table formatting
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BrianGreen
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1005
Registration date
Saturday 17 January 2015
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Last seen
30 September 2021
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30 Sep 2021 à 07:50
HelpiOS Posts 8426 Registration date Friday 30 October 2015 Status Moderator Last seen 10 May 2026 - 30 Sep 2021 à 11:00
HelpiOS Posts 8426 Registration date Friday 30 October 2015 Status Moderator Last seen 10 May 2026 - 30 Sep 2021 à 11:00
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1 response
BrianGreen
Posts
1005
Registration date
Saturday 17 January 2015
Status
Moderator
Last seen
30 September 2021
149
30 Sep 2021 à 08:37
30 Sep 2021 à 08:37
Wow - that was easy ... just changed the code a tiny bit to ...
I hope this helps someone else :^)
<?php
$result = mysqli_query($conn, "SELECT * FROM holiday_admin_bank_holiday
WHERE year=2021");
while($row = mysqli_fetch_array($result)) {
echo "<table id='open'>";
echo "<tr class='header'>";
echo "<th>Year</td>";
echo "<th>New Year</td>";
echo "<th>Easter</td></tr>";
echo "<td>".$row['year']."</td>";
echo "<td>".$row['new_year']."</td>";
echo "<td>".$row['easter']."</td></tr>";
echo "<th>Good Friday</td>";
echo "<th>May Day</td>";
echo "<th>Whitsun</td></tr>";
echo "<td>".$row['good_friday']."</td>";
echo "<td>".$row['may_day']."</td>";
echo "<td>".$row['whitsun']."</td></tr>";
echo "<th>August</td>";
echo "<th>Christmas</td>";
echo "<th>Boxing Day</td></tr>";
echo "<td>".$row['august']."</td>";
echo "<td>".$row['christmas_day']."</td>";
echo "<td>".$row['boxing_day']."</td>";
}
?>
I hope this helps someone else :^)
30 Sep 2021 à 11:00