VBA return found cell value Closed

Question

Hello,
What I have is a few rows of data, I want to search one column for data between a criteria ( 70 -71), find this data and then return the whole row back to a different range. I am having real trouble with the last bit, I can get it to return the data but in the form of first result, second result etc… can anyone suggest a correction for this? 

Private Sub CommandButton1_Click()
Dim FoundCell As Range
Dim LastCell As Range
Dim FirstAddr As String
Dim Si As Variant
Dim I As Variant

For Si = 70 To 71
         With Range("F1:F31")
         Set LastCell = .Cells(.Cells.Count)
    End With
         Set FoundCell = Range("F1:F31").find(Si, after:=LastCell)

    If Not FoundCell Is Nothing Then
        FirstAddr = FoundCell.Address
    End If

Do Until FoundCell Is Nothing
   For I = 40 To 50
        Range("a40:AD50", Cells(i, 1)) = FoundCell.EntireRow.Value
     Next i
  
    Set FoundCell = Range("F1:F31").FindNext(after:=FoundCell)
    If FoundCell.Address = FirstAddr Then
        Exit Do
    End If
    Loop
Next

    
End Sub

venkat1926 · Accepted Answer

I wonder whether you can find values between two numbers by using "find" function.
anyhow try this macro 

modify the macro to suit you. the relevant number data is in A1 down 
The relevant rows are copied in sheet 2
Sub test()
Dim rng As Range, c As Range, dest As Range
With Worksheets("sheet1")
Set rng = Range(.Range("A1"), .Range("A1").End(xlDown))
For Each c In rng
If c >= 70 And c <= 71 Then
c.EntireRow.Copy
Else
GoTo line1
End If
With Worksheets("sheet2")
Set dest = .Cells(Rows.Count, "a").End(xlUp).Offset(1, 0)
dest.PasteSpecial
End With
line1:

Next c
End With

End Sub

wil · Answer

Ta 

With a few customisations I have gotten it to work a treat!

thanks for your help.

VBA return found cell value

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