april_tat

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TrowaD

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Hi April,

So you display the value 2.0466 with 2 decimals which looks like 2.05.

When you use the function ROUND, the value will change to 2.05 instead of just visually look like 2.05.

Or you can look for the code line:

*For n = DecimalPosition + 1 To ***Len(NumStr)**

and replace it with:

*For n = DecimalPosition + 1 To ***4
**

Best regards,

Trowa

Monday, Tuesday and Thursday are usually the days I'll respond. Bear this in mind when awaiting a reply.

So you display the value 2.0466 with 2 decimals which looks like 2.05.

When you use the function ROUND, the value will change to 2.05 instead of just visually look like 2.05.

Or you can look for the code line:

Trowa

Monday, Tuesday and Thursday are usually the days I'll respond. Bear this in mind when awaiting a reply.

TrowaD

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Hi Elltee,

Here is an altered version of the WordNum function, which tackles the issues you came across:

Best regards,

Trowa

Here is an altered version of the WordNum function, which tackles the issues you came across:

Option Explicit Public Numbers As Variant, Tens As Variant Sub SetNums() Numbers = Array("", "One", "Two", "Three", "Four", "Five", "Six", "Seven", "Eight", "Nine", "Ten", "Eleven", "Twelve", "Thirteen", "Fourteen", "Fifteen", "Sixteen", "Seventeen", "Eighteen", "Nineteen") Tens = Array("", "", "Twenty", "Thirty", "Forty", "Fifty", "Sixty", "Seventy", "Eighty", "Ninety") End Sub Function WordNum(MyNumber As Double) As String Dim DecimalPosition As Integer, ValNo As Variant, StrNo As String Dim NumStr As String, n As Integer, Temp1 As String, Temp2 As String ' This macro was written by Chris Mead - www.MeadInKent.co.uk If Abs(MyNumber) > 999999999 Then WordNum = "Value too large" Exit Function End If SetNums ' String representation of amount (excl decimals) NumStr = Right("000000000" & Trim(Str(Int(Abs(MyNumber)))), 9) ValNo = Array(0, Val(Mid(NumStr, 1, 3)), Val(Mid(NumStr, 4, 3)), Val(Mid(NumStr, 7, 3))) For n = 3 To 1 Step -1 'analyse the absolute number as 3 sets of 3 digits StrNo = Format(ValNo(n), "000") If ValNo(n) > 0 Then Temp1 = GetTens(Val(Right(StrNo, 2))) If Left(StrNo, 1) <> "0" Then Temp2 = Numbers(Val(Left(StrNo, 1))) & " hundred" If Temp1 <> "" Then Temp2 = Temp2 & " and " Else Temp2 = "" End If If n = 3 Then If Temp2 = "" And ValNo(1) + ValNo(2) > 0 Then Temp2 = "and " WordNum = Trim(Temp2 & Temp1) End If If n = 2 Then WordNum = Trim(Temp2 & Temp1 & " thousand " & WordNum) If n = 1 Then WordNum = Trim(Temp2 & Temp1 & " million " & WordNum) End If Next n NumStr = Trim(Str(Abs(MyNumber))) ' Values after the decimal place DecimalPosition = InStr(NumStr, ".") Numbers(0) = "Zero" If DecimalPosition > 0 And DecimalPosition < Len(NumStr) And Len(NumStr) - DecimalPosition = 1 Then Temp1 = " point" Temp1 = Temp1 & " " & Tens(Val(Mid(NumStr, DecimalPosition + 1, 2))) WordNum = WordNum & Temp1 End If If DecimalPosition > 0 And DecimalPosition < Len(NumStr) And Len(NumStr) - DecimalPosition = 2 Then Temp1 = " point" Temp1 = Temp1 & " " & GetTens(Val(Mid(NumStr, DecimalPosition + 1, 2))) WordNum = WordNum & Temp1 End If If Len(WordNum) = 0 Or Left(WordNum, 2) = " p" Then WordNum = "Zero" & WordNum End If End Function Function GetTens(TensNum As Integer) As String ' Converts a number from 0 to 99 into text. If TensNum <= 19 Then GetTens = Numbers(TensNum) Else Dim MyNo As String MyNo = Format(TensNum, "00") GetTens = Tens(Val(Left(MyNo, 1))) & " " & Numbers(Val(Right(MyNo, 1))) End If End Function

Best regards,

Trowa

Thank you very much for suggestion. I tried to change the code, but for some reason it did not work :( .So I used Round function and it is fine. I really appreciate your advise!

April

Good to see you worked it out.

I noticed that the code adjustment only works if you have 1 number before the comma.

Changing it to:

For n = DecimalPosition + 1 To DecimalPosition + 2should do the trick.

Bet regards,

Trowa

Thank you for your help. I applied the changes and it works fine.

Do you mind me asking, - at work I have to deal with paperwork in different currencies and this macros is handy, because it does not have any particular currencies, but not the best solution, altought, I have to say it is not the best way to put in a document "Eleven point Three Seven" , it will sound nicer if I could do "Eleven dollars and Thirty Seven cents" and I know you can use SpellNimber macros for it. But because I have to use different currencies (not just USD) in different documents it is not very convenient. I was wondering, if there is a macro, which can be used for selected currencies (EUR. GBP) ? I just thought if you might suggest anything.

Once again, thank you for your help with my previous question.

April

Depending on how much currencies you work with, you can alter the macro and giving it a different name. Just look for the part in the code where the dollar and cents references are and change them.

Another possibility could be to use this formula structure:

=wordnum(INT(B1))&" "&A1& " "&wordnum(RIGHT(B1,2))&" "&A2Here the value is located in B1.

Column A will be used for the different currencies.

Then you can either change the value in cell A1 and A2 or

change the cell references in the formula (and place "Dollar and" in A3 and "cents" in A4 for example) to match the desired currency.

Example:

B1: 2500.25

A1: Euro and

A2: Eurocents

Result will be: Two thousand Five hundred Euro and Twenty Five Eurocents

Best regards,

Trowa

I thank you for the wordnum code and the currency formula you gave April, however, where the cents are 10, 20 etc, the code/formula returns "two cents" instead of "twenty cents". Also when the number is in the millions, the last two Euro digits are returned twice, as euros and as cents. Please help with this as this will be most useful for the routine I'm trying to build.

Reagrds,

EllTee.