How to convert number into text in excel [Solved/Closed]

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2
Registration date
Tuesday February 16, 2010
Last seen
February 16, 2010
- - Latest reply:  Raj - Jan 21, 2013 at 04:44 AM
Hello,
pls.send me formula to convert number into text in excel
e.g.100001 in words like' one lakh one only"
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4 replies

Best answer
220
Thank you
Formula is =WordNum(value)

Step1: press alt+F11
Step2: Insert à Module

Step3: type ='wordnum(12)' will show `Twelve'.



Option Explicit
Public Numbers As Variant, Tens As Variant

Sub SetNums()
Numbers = Array("", "One", "Two", "Three", "Four", "Five", "Six", "Seven", "Eight", "Nine", "Ten", "Eleven", "Twelve", "Thirteen", "Fourteen", "Fifteen", "Sixteen", "Seventeen", "Eighteen", "Nineteen")
Tens = Array("", "", "Twenty", "Thirty", "Forty", "Fifty", "Sixty", "Seventy", "Eighty", "Ninety")
End Sub

Function WordNum(MyNumber As Double) As String
Dim DecimalPosition As Integer, ValNo As Variant, StrNo As String
Dim NumStr As String, n As Integer, Temp1 As String, Temp2 As String
' This macro was written by Chris Mead - www.MeadInKent.co.uk

If Abs(MyNumber) > 999999999 Then
WordNum = "Value too large"
Exit Function
End If

SetNums

' String representation of amount (excl decimals)
NumStr = Right("000000000" & Trim(Str(Int(Abs(MyNumber)))), 9)
ValNo = Array(0, Val(Mid(NumStr, 1, 3)), Val(Mid(NumStr, 4, 3)), Val(Mid(NumStr, 7, 3)))

For n = 3 To 1 Step -1 'analyse the absolute number as 3 sets of 3 digits
StrNo = Format(ValNo(n), "000")

If ValNo(n) > 0 Then
Temp1 = GetTens(Val(Right(StrNo, 2)))
If Left(StrNo, 1) <> "0" Then
Temp2 = Numbers(Val(Left(StrNo, 1))) & " hundred"
If Temp1 <> "" Then Temp2 = Temp2 & " and "
Else
Temp2 = ""
End If

If n = 3 Then
If Temp2 = "" And ValNo(1) + ValNo(2) > 0 Then Temp2 = "and "
WordNum = Trim(Temp2 & Temp1)
End If

Thank you, Raj 220

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37
Thank you
Hi,

You can use the below formula.

Formula is =WordNum(value)

And in order to create this formula follow the below steps before using it.

Step1: press alt+F11
Step2: MENU: Insert  Module
Step3: copy and paste the below code and save & close the module/window.
Step4: type =’wordnum(12)’ will show ‘Twelve’.
Option Explicit
Public Numbers As Variant, Tens As Variant
Sub SetNums()
Numbers = Array("", "One", "Two", "Three", "Four", "Five", "Six", "Seven", "Eight", "Nine", "Ten", "Eleven", "Twelve", "Thirteen", "Fourteen", "Fifteen", "Sixteen", "Seventeen", "Eighteen", "Nineteen")
Tens = Array("", "", "Twenty", "Thirty", "Forty", "Fifty", "Sixty", "Seventy", "Eighty", "Ninety")
End Sub
Function WordNum(MyNumber As Double) As String
Dim DecimalPosition As Integer, ValNo As Variant, StrNo As String
Dim NumStr As String, n As Integer, Temp1 As String, Temp2 As String
' This macro was written by Chris Mead - www.MeadInKent.co.uk
If Abs(MyNumber) > 999999999 Then
WordNum = "Value too large"
Exit Function
End If
SetNums
' String representation of amount (excl decimals)
NumStr = Right("000000000" & Trim(Str(Int(Abs(MyNumber)))), 9)
ValNo = Array(0, Val(Mid(NumStr, 1, 3)), Val(Mid(NumStr, 4, 3)), Val(Mid(NumStr, 7, 3)))
For n = 3 To 1 Step -1 'analyse the absolute number as 3 sets of 3 digits
StrNo = Format(ValNo(n), "000")
If ValNo(n) > 0 Then
Temp1 = GetTens(Val(Right(StrNo, 2)))
If Left(StrNo, 1) <> "0" Then
Temp2 = Numbers(Val(Left(StrNo, 1))) & " hundred"
If Temp1 <> "" Then Temp2 = Temp2 & " and "
Else
Temp2 = ""
End If
If n = 3 Then
If Temp2 = "" And ValNo(1) + ValNo(2) > 0 Then Temp2 = "and "
WordNum = Trim(Temp2 & Temp1)
End If
If n = 2 Then WordNum = Trim(Temp2 & Temp1 & " thousand " & WordNum)
If n = 1 Then WordNum = Trim(Temp2 & Temp1 & " million " & WordNum)
End If
Next n
NumStr = Trim(Str(Abs(MyNumber)))
' Values after the decimal place
DecimalPosition = InStr(NumStr, ".")
Numbers(0) = "Zero"
If DecimalPosition > 0 And DecimalPosition < Len(NumStr) Then
Temp1 = " point"
For n = DecimalPosition + 1 To Len(NumStr)
Temp1 = Temp1 & " " & Numbers(Val(Mid(NumStr, n, 1)))
Next n
WordNum = WordNum & Temp1
End If
If Len(WordNum) = 0 Or Left(WordNum, 2) = " p" Then
WordNum = "Zero" & WordNum
End If
End Function
Function GetTens(TensNum As Integer) As String
' Converts a number from 0 to 99 into text.
If TensNum <= 19 Then
GetTens = Numbers(TensNum)
Else
Dim MyNo As String
MyNo = Format(TensNum, "00")
GetTens = Tens(Val(Left(MyNo, 1))) & " " & Numbers(Val(Right(MyNo, 1)))
End If
End Function
your formula ok but close the sheet after open the sheet not working any other way plz send me my mail id sandeep_0486@yahoo.co.in
Thanks you are brilliant
hello dear
your code is nice.but here a deaufault.
when I close excel programe and reopen fresh excel page. and when I used same formulal. the formuula had been losed why.
pls give a code that run every time in excel.
rizvisa1
Posts
4476
Registration date
Thursday January 28, 2010
Status
Contributor
Last seen
January 6, 2016
-
Sudir
If you want this formula to be always there in excel. Start a new excel and save this code in that book. When you save this new book, choose "SAVE AS" and from file type select XLA if you are on pre 2007 excel and XLSA (i think thats what 2007 says). Basically you have to save it as addin
Posts
4476
Registration date
Thursday January 28, 2010
Status
Contributor
Last seen
January 6, 2016
14
Thank you
See this

http://ccm.net/...
14
Thank you
please tell me how to convert nuneric to english in Excel
You can use the below formula.

Formula is =WordNum(value)

And in order to create this formula follow the below steps before using it.

Step1: press alt+F11
Step2: MENU: Insert ? Module
Step3: copy and paste the below code and save & close the module/window.
Step4: type ='wordnum(12)' will show `Twelve'.
Option Explicit
Public Numbers As Variant, Tens As Variant
Sub SetNums()
Numbers = Array("", "One", "Two", "Three", "Four", "Five", "Six", "Seven", "Eight", "Nine", "Ten", "Eleven", "Twelve", "Thirteen", "Fourteen", "Fifteen", "Sixteen", "Seventeen", "Eighteen", "Nineteen")
Tens = Array("", "", "Twenty", "Thirty", "Forty", "Fifty", "Sixty", "Seventy", "Eighty", "Ninety")
End Sub
Function WordNum(MyNumber As Double) As String
Dim DecimalPosition As Integer, ValNo As Variant, StrNo As String
Dim NumStr As String, n As Integer, Temp1 As String, Temp2 As String
' This macro was written by Chris Mead - www.MeadInKent.co.uk
If Abs(MyNumber) > 999999999 Then
WordNum = "Value too large"
Exit Function
End If
SetNums
' String representation of amount (excl decimals)
NumStr = Right("000000000" & Trim(Str(Int(Abs(MyNumber)))), 9)
ValNo = Array(0, Val(Mid(NumStr, 1, 3)), Val(Mid(NumStr, 4, 3)), Val(Mid(NumStr, 7, 3)))
For n = 3 To 1 Step -1 'analyse the absolute number as 3 sets of 3 digits
StrNo = Format(ValNo(n), "000")
If ValNo(n) > 0 Then
Temp1 = GetTens(Val(Right(StrNo, 2)))
If Left(StrNo, 1) <> "0" Then
Temp2 = Numbers(Val(Left(StrNo, 1))) & " hundred"
If Temp1 <> "" Then Temp2 = Temp2 & " and "
Else
Temp2 = ""
End If
If n = 3 Then
If Temp2 = "" And ValNo(1) + ValNo(2) > 0 Then Temp2 = "and "
WordNum = Trim(Temp2 & Temp1)
End If
If n = 2 Then WordNum = Trim(Temp2 & Temp1 & " thousand " & WordNum)
If n = 1 Then WordNum = Trim(Temp2 & Temp1 & " million " & WordNum)
End If
Next n
NumStr = Trim(Str(Abs(MyNumber)))
' Values after the decimal place
DecimalPosition = InStr(NumStr, ".")
Numbers(0) = "Zero"
If DecimalPosition > 0 And DecimalPosition < Len(NumStr) Then
Temp1 = " point"
For n = DecimalPosition + 1 To Len(NumStr)
Temp1 = Temp1 & " " & Numbers(Val(Mid(NumStr, n, 1)))
Next n
WordNum = WordNum & Temp1
End If
If Len(WordNum) = 0 Or Left(WordNum, 2) = " p" Then
WordNum = "Zero" & WordNum
End If
End Function
Function GetTens(TensNum As Integer) As String
' Converts a number from 0 to 99 into text.
If TensNum <= 19 Then
GetTens = Numbers(TensNum)
Else
Dim MyNo As String
MyNo = Format(TensNum, "00")
GetTens = Tens(Val(Left(MyNo, 1))) & " " & Numbers(Val(Right(MyNo, 1)))
End If
End Function