Related:
- Find and replace a word in a string
- Number to text in word - Guide
- Insert a tick in word - Guide
- Microsoft word free download - Download - Word processors
- How to insert a line in word for resume - Guide
- Word free for u - Guide
2 responses
venkat1926
Posts
1863
Registration date
Sunday June 14, 2009
Status
Contributor
Last seen
August 7, 2021
811
Mar 22, 2012 at 10:50 PM
Mar 22, 2012 at 10:50 PM
many ways of doing it.
following macro is little structured so that you can understand the steps
type
int_dog int (10)
in A1
then run this macro
following macro is little structured so that you can understand the steps
type
int_dog int (10)
in A1
then run this macro
Sub test()
Dim x As String, xx As String, j As Integer, y As String, xxx As String
x = Range("a1").Value
xx = "int"
j = Len(xx)
y = InStr(j + 1, x, xx)
'MsgBox y
xxx = Left(x, y - 1) & "number" & Right(x, Len(x) - j - y)
MsgBox xxx
End Sub
venkat1926
Posts
1863
Registration date
Sunday June 14, 2009
Status
Contributor
Last seen
August 7, 2021
811
Mar 26, 2012 at 01:23 AM
Mar 26, 2012 at 01:23 AM
TRY THIS MACRO . the result is in column B
the data and result will be like this finally
existing string corrected string
person_name name person_name size
place_name name place_name size
animal_name name animal_name size
item_name name item_name size
Sub test()
Dim r As Range, c As Range, j As Long, x As String, xx As String
Set r = Range(Range("A2"), Range("A2").End(xlDown))
x = "name"
'DEFINITION OF x MAY BE CHANGED WHEN NECESSARY
j = Len(x)
For Each c In r
xx = Left(c.Value, Len(c.Value) - j - 1) & " " & "size"
'MsgBox xx
c.Offset(0, 1) = xx
Next c
End Sub
the data and result will be like this finally
existing string corrected string
person_name name person_name size
place_name name place_name size
animal_name name animal_name size
item_name name item_name size
Mar 25, 2012 at 04:17 AM
but i guess the example explained above by me is not clear...
the scenario is like this...
I have data in range A1 to A50 which have values as below:
person_name name,
place_name name ,
animal_name name,
item_name name
.
.
. and so on.
Now the first string in A1 is as below
person_name name,
I want to replace second occurrence of "name" (which is after space) in this string with "size" and output should be as below:
person_name size,
place_name size
.
.
and so on
But what I am getting is
person_size size,
place_size size,
.
. and so on.
How can I stop the first occurrence of "name" which is with underscore from not getting replaced.
Can I use some delimiter property or make use of the underscore with the first occurrence of name??
Mar 28, 2012 at 03:09 PM
but the above code is giving me compilation error