Help regarding a pricing sheet
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Kev1027
-
19 Aug 2016 à 20:41
Kev1027 Posts 2 Registration date Friday 19 August 2016 Status Member Last seen 19 August 2016 - 19 Aug 2016 à 22:55
Kev1027 Posts 2 Registration date Friday 19 August 2016 Status Member Last seen 19 August 2016 - 19 Aug 2016 à 22:55
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4 responses
Welcome Kev.....
The If formula is as such:
=IF(logic_test,true,false)
You can nest IF's (if this applies to you):
=IF(logic_test1,=IF(logic_test2,true2,false2),false1)
Let us know if you have any problems!
Have fun!
The If formula is as such:
=IF(logic_test,true,false)
You can nest IF's (if this applies to you):
=IF(logic_test1,=IF(logic_test2,true2,false2),false1)
Let us know if you have any problems!
Have fun!
fdibbins
Posts
33
Registration date
Sunday 19 June 2016
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Contributor
Last seen
20 November 2016
1
19 Aug 2016 à 22:40
19 Aug 2016 à 22:40
1st, I think you have the 2nd sign in your request the wrong way round. I think the 2nd sign should be less than, not greater than.
Anyway, try this...
=IF(C5>10000,105000,IF(C5>7500,95000,IF(C5>5000,85000,75000)))
Anyway, try this...
=IF(C5>10000,105000,IF(C5>7500,95000,IF(C5>5000,85000,75000)))
Kev1027
Posts
2
Registration date
Friday 19 August 2016
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Member
Last seen
19 August 2016
19 Aug 2016 à 20:52
19 Aug 2016 à 20:52
Thanks for the quick response ac3mark,
I'm afraid I may need a bit more detail from you. Here is what I have so far:
=IF(C5<=4999,75000,75000+10000) and I am not sure how to set up from here so that what ever number they enter in C5, C15 increase appropriately.
Thanks!
I'm afraid I may need a bit more detail from you. Here is what I have so far:
=IF(C5<=4999,75000,75000+10000) and I am not sure how to set up from here so that what ever number they enter in C5, C15 increase appropriately.
Thanks!
Kev1027
Posts
2
Registration date
Friday 19 August 2016
Status
Member
Last seen
19 August 2016
19 Aug 2016 à 22:55
19 Aug 2016 à 22:55
Hello fdibbins,
Thanks for your response! You are correct, thanks for the correction!
This works perfectly, however, in C5 a number as high as 600,000 could be entered. Is there away to do this with out having to build each one of the references?
Thanks!
Thanks for your response! You are correct, thanks for the correction!
This works perfectly, however, in C5 a number as high as 600,000 could be entered. Is there away to do this with out having to build each one of the references?
Thanks!