How to create a image.php (show ip +background) [Closed]

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1
Registration date
Monday August 7, 2017
Status
Member
Last seen
August 7, 2017
-
i can't combine these codes i tested but not work

<?php
$img_number = imagecreate(275,225);
$backcolor = imagecolorallocate($img_number,102,102,153);
$textcolor = imagecolorallocate($img_number,205,205,205);

imagefill($img_number,0,0,$backcolor);
$number = " Your IP is $_SERVER[REMOTE_ADDR]";

Imagestring($img_number,10,5,5,$number,$textcolor);

header("Content-type: image/jpeg");
imagejpeg($img_number);
?>

+ background

<?php
$im = imagecreatefrompng("imagetest.png");

header('Content-Type: image/png');

imagepng($im);
imagedestroy($im);
?>

in a file (image.php) /please help me /thanks
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2 replies

Posts
1
Registration date
Friday March 2, 2018
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Member
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March 2, 2018
0
Thank you
You can't evaluate PHP in a CSS file. The only way to do this with PHP is to set the CSS value as an inline CSS value.
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13036
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Monday June 3, 2013
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Moderator
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October 11, 2019
1463
0
Thank you
What error are you getting?