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How to create a image.php (show ip +background) [Closed]

tmmovie 1 Posts Monday August 7, 2017Registration date August 7, 2017 Last seen - Aug 7, 2017 at 04:27 AM - Latest reply: ac3mark 10759 Posts Monday June 3, 2013Registration dateModeratorStatus November 2, 2018 Last seen
- Mar 2, 2018 at 07:27 PM
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i can't combine these codes i tested but not work 

<?php
$img_number = imagecreate(275,225);
$backcolor = imagecolorallocate($img_number,102,102,153);
$textcolor = imagecolorallocate($img_number,205,205,205);

imagefill($img_number,0,0,$backcolor);
$number = " Your IP is $_SERVER[REMOTE_ADDR]";

Imagestring($img_number,10,5,5,$number,$textcolor);

header("Content-type: image/jpeg");
imagejpeg($img_number);
?>

+ background 

<?php
$im = imagecreatefrompng("imagetest.png");

header('Content-Type: image/png');

imagepng($im);
imagedestroy($im);
?>

in a file (image.php) /please help me /thanks
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2 replies

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JohnyArts 1 Posts Friday March 2, 2018Registration date March 2, 2018 Last seen - Mar 2, 2018 at 06:57 AM
0
Thank you
You can't evaluate PHP in a CSS file. The only way to do this with PHP is to set the CSS value as an inline CSS value.
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ac3mark 10759 Posts Monday June 3, 2013Registration dateModeratorStatus November 2, 2018 Last seen - Mar 2, 2018 at 07:27 PM
0
Thank you
What error are you getting?
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