I'm working on developing a menu for a USB flash drive.
I have .bat file that opens a spreadsheet with a program that is installed on the flash drive.
The code looks something like this:
Start /d \Folder1\folder2\folderofprogram Name of program.exe "Name of file.ods"
This code works well but the problem is I need to have the file in the same directory as the program.
Is there a way to make the .bat file open the file from a different directory on the USB flash drive?
I think this is a simple problem but was not able to find any information about it.
It depends on where the bat-file itself resides on what program you try to start etc. For instance, to get the drive letter of the batch file path you could use SET DRIVE=%~d0 in your batch file. On the command line (cmd.exe) have a look at "help for", this might help you with this. Or have a look at http://www.robvanderwoude.com/batchhowto.php .
I know it will take some time to master this... I'm sorry I can't come up with a ready-to-use solution.