Conversion of DOB to full words

Solved/Closed
jigs - Feb 20, 2016 at 09:06 PM
gane@1987 Posts 1 Registration date Friday March 3, 2017 Status Member Last seen March 3, 2017 - Mar 3, 2017 at 10:12 AM
Hello,





I want to to convert dob to word like 5/6/2014 to fifth June two thousand fourteen please tell me solution
Related:

4 responses

vcoolio Posts 1411 Registration date Thursday July 24, 2014 Status Moderator Last seen September 6, 2024 262
Feb 21, 2016 at 04:26 AM
Hello Jigs,

This will require a UDF (User Defined Function), not just a simple formula.

Read the following post (post #2) by Rick Rothstein way back in 2012. He has supplied an excellent solution for the OP which will work for you also.

https://www.mrexcel.com/board/threads/convert-date-to-words.615519/

Place the UDF in a standard module. I have modified it as follows to allow for proper English grammar and punctuation in the end result:-


Function DateToWords(ByVal DateIn As Variant) As String
  Dim Yrs As String
  Dim Hundreds As String
  Dim Decades As String
  Dim Tens As Variant
  Dim Ordinal As Variant
  Dim Cardinal As Variant
  Ordinal = Array("First", "Second", "Third", _
                   "Fourth", "Fifth", "Sixth", _
                   "Seventh", "Eighth", "Nineth", _
                   "Tenth", "Eleventh", "Twelfth", _
                   "Thirteenth", "Fourteenth", _
                   "Fifteenth", "Sixteenth", _
                   "Seventeenth", "Eighteenth", _
                   "Nineteenth", "Twentieth", _
                   "Twenty first", "Twenty second", _
                   "Twenty third", "Twenty fourth", _
                   "Twenty fifth", "Twenty sixth", _
                   "Twenty seventh", "Twenty eighth", _
                   "Twenty nineth", "Thirtieth", _
                   "Thirty first")
  Cardinal = Array("", "One", "Two", "Three", "Four", _
                   "Five", "Six", "Seven", "Eight", "Nine", _
                   "Ten", "Eleven", "Twelve", "Thirteen", _
                   "Fourteen", "Fifteen", "Sixteen", _
                   "Seventeen", "Eighteen", "Nineteen")
  Tens = Array("Twenty", "Thirty", "Forty", "Fifty", _
               "Sixty", "Seventy", "Eighty", "Ninety")
  DateIn = CDate(DateIn)
  Yrs = CStr(Year(DateIn))
  Decades = Mid$(Yrs, 3)
  If CInt(Decades) < 20 Then
    Decades = Cardinal(CInt(Decades))
  Else
    Decades = Tens(CInt(Left$(Decades, 1)) - 2) & " " & _
              Cardinal(CInt(Right$(Decades, 1)))
  End If
  Hundreds = Mid$(Yrs, 2, 1)
  If CInt(Hundreds) Then
    Hundreds = Cardinal(CInt(Hundreds)) & " Hundred and "
  Else
    Hundreds = ""
  End If
  DateToWords = Ordinal(Day(DateIn) - 1) & " day of " & _
                Format$(DateIn, "mmmm, ") & _
                Cardinal(CInt(Left$(Yrs, 1))) & _
                " Thousand, " & Hundreds & Decades
End Function


If your date is in say, cell A1, place this formula in cell B1 (or wherever you like):
=DateToWords(A1)


Read Rick's post carefully and remember that this is his work solely.

I hope that this helps.

Cheerio,
vcoolio.
0
Hello while using this Formula I got oñly one answer please help me to solve this error
0
Thank you friend I got my solution.
0
gane@1987 Posts 1 Registration date Friday March 3, 2017 Status Member Last seen March 3, 2017
Mar 3, 2017 at 10:12 AM
Function DateToWords(ByVal DateIn As Variant) As String
Dim Yrs As String
Dim Hundreds As String
Dim Decades As String
Dim Tens As Variant
Dim Ordinal As Variant
Dim Cardinal As Variant
Ordinal = Array("First", "Second", "Third", _
"Fourth", "Fifth", "Sixth", _
"Seventh", "Eighth", "Nineth", _
"Tenth", "Eleventh", "Twelfth", _
"Thirteenth", "Fourteenth", _
"Fifteenth", "Sixteenth", _
"Seventeenth", "Eighteenth", _
"Nineteenth", "Twentieth", _
"Twenty first", "Twenty second", _
"Twenty third", "Twenty fourth", _
"Twenty fifth", "Twenty sixth", _
"Twenty seventh", "Twenty eighth", _
"Twenty nineth", "Thirtieth", _
"Thirty first")
Cardinal = Array("", "One", "Two", "Three", "Four", _
"Five", "Six", "Seven", "Eight", "Nine", _
"Ten", "Eleven", "Twelve", "Thirteen", _
"Fourteen", "Fifteen", "Sixteen", _
"Seventeen", "Eighteen", "Nineteen")
Tens = Array("Twenty", "Thirty", "Forty", "Fifty", _
"Sixty", "Seventy", "Eighty", "Ninety")
DateIn = CDate(DateIn)
Yrs = CStr(Year(DateIn))
Decades = Mid$(Yrs, 3)
If CInt(Decades) < 20 Then
Decades = Cardinal(CInt(Decades))
Else
Decades = Tens(CInt(Left$(Decades, 1)) - 2) & " " & _
Cardinal(CInt(Right$(Decades, 1)))
End If
Hundreds = Mid$(Yrs, 2, 1)
If CInt(Hundreds) Then
Hundreds = Cardinal(CInt(Hundreds)) & " Hundred and "
Else
Hundreds = ""
End If
DateToWords = Ordinal(Day(DateIn) - 1) & " day of " & _
Format$(DateIn, "mmmm, ") & _
Cardinal(CInt(Left$(Yrs, 1))) & _
" Thousand, " & Hundreds & Decades
End Function



If your date is in say, cell A1, place this formula in cell B1 (or wherever you like):

=DateToWords(A1)


A1-- 23/09/1995

B1--Twenty third day of September, One Thousand, Nine Hundred and Ninety Five.

I want this type of format.. please help how it work...

A1--22/02/2012
B1--Twenty Two February, Two Thousand Tweleve.

please help Dear users.
0